PRECALCULUS NAME___________________
DESIGNER GENES
Suppose
Blondie has blonde hair and her spouse Dagwood has brown hair. What are the
chances that their children will have brown hair?
PUNNETT
SQUARES
Hair
or eye color are traits that are genetically determined. You get one gene from
your mother and one gene from your father. For many of your traits you have
either two dominant genes (called homozygous dominant), two recessive genes
(called homozygous recessive), or one of each type (called heterozygous or
hybrid). A dominant gene is usually denoted by a capital letter, say B,
and a recessive gene for the same trait is denoted by a lower case letter, say b.
So,
BB is homozygous dominant,
bb is homozygous recessive, and
Bb is heterozygous dominant.
|
|
B |
b |
|
B |
BB |
Bb |
|
b |
Bb |
bb |
We
can set up what is called in biology a Punnett square
to help determine the probability of getting brown hair. Historically, we know
that brown hair is dominant to blonde hair. Thus, a Punnett
square for this scenario might look like this.
So
there are four possible outcomes. Three of these (BB, Bb, Bb) will result in
brown hair, and one (bb) will result in blonde hair. Thus, the probability of
brown hair is ¾ , and the probability of blonde hair is ¼.
|
|
2 |
1 |
|
2 |
4 |
3 |
|
1 |
3 |
2 |
We
can set up a simulation to help determine this probability by using the randint command on your calculator. First we need to
numerically code each of the possible genes. Let B = 2 and b = 1. Then we need
to decide how to describe the joining of the genes in a numerical way. Using
addition seems reasonable. So the numbered “Punnett
square” might look like this:
Thus,
getting a sum greater than 3 would result in brown hair.
SIMULATIONS
To
design a simulation of this situation, generate a list of 100 random integers
between 1 and 2 inclusive in L1. Do the same in L2. Create L3 so that it is L1
+ L2. Display your results from L3 in a histogram using an appropriate window.
Draw your histogram below.
What
do you notice about the frequency distribution? Is it close to what you would
expect from the theoretical probability?
Generating
a simulation for such a small Punnett square seems to
be more cumbersome than actually writing the square itself. However, when
considering two or more traits, the Punnett square
can be rather unwieldy to form. Now your are ready to answer the question
originally posed at the top of this page. “What is the probability that a
person would have brown hair and blue eyes with a mother who has blonde hair
and blue eyes and a father who has brown hair and brown eyes?” (Note that blue
eyes are recessive to brown eyes.) Try to use a simulation to model your
scenario.
TEACHER’S
NOTES FOR DESIGNER GENES LAB
|
|
B |
B |
|
B |
BB |
BB |
|
B |
BB |
BB |
|
|
B |
B |
|
B |
BB |
BB |
|
b |
Bb |
Bb |
100% brown hair 100%
brown hair